Question

LAB VI. DETERMINING AN EMPIRICAL FORMULA DATA SHEET NAMES: Ricardo Sierra #27 SECTION: Trial #2 2.2.15 1. Mass of crucible, lid and Mg.g Trial #1 22.666 7.) 340 0.312 2. Mass of crucible and lid, g 22.340 0.312 3. Mass of magnesium, s (line 1 - line 2) 22.840 22.840 4. Mass of crucible, lid and magnesium oxide, g (AFTER WATER TREATMENT AND COOLING) 0.5 0.5 5. Mass of magnesium oxide, (line 4-line 2) 0.188 6. Mass of oxygen, g (line 5 - line 3) 7. Moles of magnesium (Use three significant figures) 8. Moles of oxygen (Use three significant figures) 9. Ratio of moles of Mg to moles of O 10. Empirical formula of magnesium oxide

Answer 1

Неис, Trial - 1 mals of magnesium, g = (line 1- line 2) Go To 0.3129 molar weight of Magnesium = 24-305 gmol moles of Mq = mass of magnesium moles of mg - Molar weight of magnesium 0:3129 0.0128 moles 24-3059 Imol & mass of oxygen, 9 - (line 5- line 3) molar mars of oxygen = 160g Нелсе, moles of a = mass of oxygen (ing) " Molar mass of 2 do mass of oxygen, g = 0.1889 = 0.1889 - 0-0118 motes 16:09 May 0.0128 - 1.08 to. Em the ratio of rical formen de my 19. Ratio of mole of ug to mous of o moles molis ñ oo 0.0118 I no. Emperical formula of magnesium oxide is the ratio of moles of nego: motes of 0-1 Hence, emperical formula Mg, 0, similarly for trial 2, .