Resources Hint Check Answer < Question 38 of 39 > Calculate the pH at the equivalence...

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Answer 1

Answer #1

CH3NH2 + HCl ____________> CH3NH3Cl

V x0.15 Vx0.15 0 initial mmoles

00 0 Vx0.15 at equivalence

thus the [salt] = mmoles/ total volume = Vx0.15/(V+V) = 0.075 M

pKb of base = -log 5x10-4 = 3.3010

The pH of salt of weak base with strong acid (acidic due to cationic hydrolysis) is given by

pH = 1/2[pKw-pKb - log C]

= 1/2 [ 14 - 3.3010 -log 0.075]

= 5.911

Answer 2

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