[H+] = Kw / [OH-] , Kw = ionic product of water = 10-14
= 10-14 / [2.66 * 10-8]
= 3.75 * 10-7
hence, pH = - log [3.75 * 10-7] = 6.42
Assignment Score: 75.7% Resources Hint Check < Question 28 of 33 > Calculate the pH of...
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