< Question 13 of 14 > What is the value of K for this aqueous reaction...
Calculate AG° (kJ/mole) at 298 K for the reaction below: H2SO4(1) <H2O(1)+ SO3(g) K=2.07 x 10-12 Enter a number to 2 decimal places.
Predict delta G and the product assuming presence of acid or base catalyst as needed. HOCH CH2OH CH3 * ? AG° <0 kJ/mol AGⓇ=0 kJ/mol AG° >0 kJ/mol CH3OH NH2 ? AG° <0 kJ/mol AG° 20 kJ/mol AG° >0 kJ/mol -ОН С. ОСН3 ДG° <0 kJ/mol AG° 0 kJ/mol ДG° >0 kJ/mol CH3NH2 ? ОН AG° <0 kJ/mol AG° 0 kJ/mol AGⓇ>0 kJ/mol
Predict the delta G and the product assuming presence of acid or base catalyst as needed. 0: SOCI2 ? OH AG° <0 kJ/mol AG° 0 kJ/mol AG° >0 kJ/mol CH3NH2 - ? H H AG° <0 kJ/mol AG° 0 kJ/mol AG° >0 kJ/mol O: CH3OH ? HOOL CH3 AG° <0 kJ/mol AG° 0 kJ/mol AG° >0 kJ/mol CH3OH CF3 - ? AG° <0 kJ/mol AG° 0 kJ/mol AG° > kJ/mol
What is the value of K for this aqueous reaction at 298 K? A + B F C + D AG° = 15.82 kJ/mol KE 0
Predict delta G and the product assuming presence of acid or base catalyst as needed. NH ? OCH3 AG° <0 kJ/mol AG° 20 kJ/mol AG° >0 kJ/mol O: ОН - ? Br AG° <0 kJ/mol AG° 0 kJ/mol AGº > kJ/mol H/Pt ? AG° <0 kJ/mol AG° 0 kJ/mol AGⓇ>0 kJ/mol NaOH CH3 ? (2 eq.) AG° <0 kJ/mol AG° 0 kJ/mol om AGº >0 kJ/mol
What is the value of K for this aqueous reaction at 298 K? A+B = C+D AG° = 19.57 kJ/mol K =
What is the value of K for this aqueous reaction at 298 K? A+B=C+D AG° = 29.82 kJ/mol K=
What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG = 21.79 kJ/mol -6601
Q=K Q1 Question 14 What is the pH of a 1.00 L solution that is 0.15 M HCNO and 0.10 M NaCNO after 0.05 moles of strong base have been added? K, CH 3.88 4.30 3.10 12.70 3.70 Question 15 Determine the equilibrium constant for the following reaction at 298 K. С ЕООРГО Question 13 When AG = 0 for a reaction: K=1 K=0 Q<K Q=K Q=1 MacBook Pro
What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 15.08 kJ/mol K = 1.661 x10-6