In a double-slit experiment it is found that blue light of wavelength 467 nm gives a...

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In a double-slit experiment it is found that blue light of wavelength 467 nm gives a...

In a double-slit experiment it is found that blue light of wavelength 467 nm gives a second-order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location?

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Answer 1

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Answer #1

Given that

The wavelength of the blue light(λ_b) = 467nm

For the maxima of second order for blue light

We have dsinθ = mλb

dsinθ= 934nm

For a minimum interference of the other light

dsinθ = (m+1/2)λ

934nm =(m+1/2)λ

Where m =0,1,2,3................

For the first 3 values of m we get

If m =0 then 934nm = (1/2)λ then λ = 1868nm

If m=1 then 934nm = (3/2)λ then λ =623nm

If m=2 then 934nm = (5/2)λ then λ = 374nm

Therefore the only wavelength in the visible light is (λ)=623nm

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Answer 2

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