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Answer #1

Magnetic field due to the current carrying wire is, \(B=\frac{\mu_{0} I}{2 \pi r}\)

The magnetic force is, \(F=q v \times B\)

Here, the magnetic field from the wire is coming out of the page at the charge and \(q\) is negative. From the equation \(F=q v \times B\) Then the force is upwards. Hence, the correct answer is option \(\mathrm{c}\).

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A negatively charged particle is moving to the right, directly above a wire having a current...
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