Question

Chargaff's results yielded a molar ratio of 1.45 for A to G in hen DNA, 1.29 for T to C, 1.06 for A to T, and 0.910 for G to C. The ratio of purines to pyrimidines is 0.990. Calculate the mole fractions of A, G, T and C in hen DNA.

Mole fraction of A =

Mole fraction of G =

Mole fraction of T =

Mole fraction of C

Answer 1

- 1.45 - 1.45 7 = -2१ 1 = 129 4 - 1- 06 A+4 0.940 00 0283 - २१ , C→ 0.283 - 1:29 ८ - ०१ A = 106 A _ -1.06 0.283 | A = 0.५१११ A = 145 4 -०.१10 T+c A+T+ ++ ८ = 1 A+ 4 = 1 - (T+C) ।- (T+c) - ०.११० - TTC |-T- - ०.११T + 0.११८ | = १११ + ११८ T+ c= ) T=२१ T+ ११ T (I+4)-११ T= १० __T १ . = [0-283 • 1 9.२१११ - 4 1.45 (- 0-20687 1-29 1.११ र

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