Question

Biology 355, Spring 2020 Problem Set 5. Due 3/10/19 at 2PM on iLearn 1. Do we expect a son/daughter to have a trait if the tr
0 0
Add a comment Improve this question Transcribed image text
Answer #1

ANS 1- Y LINKED INHERITANCE

DAUGHTER SON

MOM HAS TRAIT W W

DAD HAS TRAIT N Y

BOTH HAVE TRAIT W W

NEITHER HAVE TRAIT N N

ANS 2- MITOCHONDRIAL INHERITANCE

DAUGHTER SON

MOM HAS TRAIT P P

DAD HAS TRAIT N N

BOTH HAVE TRAIT P P

NEITHER HAVE TRAIT N N

ANS 3- AUTOSOMAL DOMINANT

DAUGHTER SON

MOM HAS TRAIT Y Y

DAD HAS TRAIT Y Y

BOTH HAVE TRAIT Y Y

NEITHER HAVE TRAIT N N

ANS 4- AUTOSOMAL RECESSIVE

DAUGHTER SON

MOM HAS TRAIT   N N

DAD HAS TRAIT N N

BOTH HAVE TRAIT Y Y

NEITHER HAVE TRAIT N N

Add a comment
Know the answer?
Add Answer to:
Biology 355, Spring 2020 Problem Set 5. Due 3/10/19 at 2PM on iLearn 1. Do we...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Both have trait Neither have trait X-linked recessive Daughter Son Mom has trait Dad has trait...

    Both have trait Neither have trait X-linked recessive Daughter Son Mom has trait Dad has trait Both have trait Neither have trait X-linked male-limited Daughter Mom has trait Dad has trait Both have trait Neither have trait Son Imprinting Daughter Son Mom has trait Dad has trait Both have trait Neither have trait Polygenic Daughter Son Mom has trait Dad has trait Both have trait Neither have trait 2. You nip a penny, a nickel, a dime and a quarter....

  • 19. Your colleague is studying long toes in the California towhee. She proposes that this trait...

    19. Your colleague is studying long toes in the California towhee. She proposes that this trait is! due to to an Z-linked dominant allele. You go for a hike in Oakland, and notice that only few of the California towhees you see have the long toe trait. Does this affect your colleague's hypothesis? How? Why? (2 points) You go for a walk in Golden Gate Park, and notice that, among California towhees in the Golden Gate population, females are more...

  • question 5-52 93 Dd D) dd D) aa x aa C) human height E) DI 4.Which...

    question 5-52 93 Dd D) dd D) aa x aa C) human height E) DI 4.Which of these crosses will only produce heterozygous offspring? B) AA x Aa C) Aa x Aa E) Aa x aa 5. Which of the following human traits is an example of codominance? A) sickle-cell anemia D) AB blood type B) variation in eye color 6. Which of the following is true regarding an individual who has inherited one sickle-cell gene and one normal gene...

  • sono ben sooloo 5. Katie is a college student who comes into the student health clinic...

    sono ben sooloo 5. Katie is a college student who comes into the student health clinic in great distress. As a clinic staff member, you learn that Katie has just found out that her mother was diagnosed with Huntingtons disease an ultimately fatal inherited disorder). After he found out about his wife's diagnosis, Katie's Dad was tested to see if he had a Huntington's disease allele and the test came back negative (he doesn't have the allele). Katie's Dad is...

  • I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that...

    I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...

  • the two cream colored guinea pigs produced, in one case, 22 yellow. 47cream, and 19 white....

    the two cream colored guinea pigs produced, in one case, 22 yellow. 47cream, and 19 white. What type of inheritance is this? II. Sex-linked Characteristics 12. In man, colorblindness, an inability to distinguish between red and green, is inherited as a sex-linked character on the X chromosome. It is recessive. If a colorblind man marries a homozygous normal woman what chance is there for the children of being colorblind? If a normal man marries a colorblind woman. where will colorblindness...

  • 2 The inheritance of autosomal dominant traits also can be explored through pedigree analysis, Polydactylism, having...

    2 The inheritance of autosomal dominant traits also can be explored through pedigree analysis, Polydactylism, having extra digits, results from a dominant gene (P). Using Figure 3.8, explain the appearance of polydactyly in children of generation 3. O IIION FUR 8.8 Polydactylism pedigree. X-linked traits are carried exclusively on the X chromosome. Because a male possesses only one X chromosome, if he receives an X chromosome that carries an X-linked trat he will express that trait. For a female to...

  • Problem on genetics, Please solve for what is asking for the first and the second pedigree,...

    Problem on genetics, Please solve for what is asking for the first and the second pedigree, I have included every single detail that is helpful to the problem Antoine’s narrative: I have a sister who has sickle cell disease. She is not married. Neither my mom nor my dad has the disease. My mother has two brothers and one sister, although one of her brothers passed away when I was very young from complications of sickle cell anemia. Neither my...

  • How to do 21 and 23? 50 map units 5 map units Linkage groups d. 92...

    How to do 21 and 23? 50 map units 5 map units Linkage groups d. 92 ty results from a rare, sex-limited nal puberty (P) and is expressed brother Jack and his sister Beth 10 and 14. Although Bill's mother uncles (his mother's brothers) underwent normal puberty. aploid sets of e nucleolar organizers for numbers 17-20 below) Male-limited precocious puberty results autosomal allele (P) that is dominant over the allele for normal pube only in males. Bill undergoes precocious puberty,...

  • How to do 23? 50 map units 5 map units Linkage groups d. 92 ty results...

    How to do 23? 50 map units 5 map units Linkage groups d. 92 ty results from a rare, sex-limited nal puberty (P) and is expressed brother Jack and his sister Beth 10 and 14. Although Bill's mother uncles (his mother's brothers) underwent normal puberty. aploid sets of e nucleolar organizers for numbers 17-20 below) Male-limited precocious puberty results autosomal allele (P) that is dominant over the allele for normal pube only in males. Bill undergoes precocious puberty, but his...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT