Answer-
According to the given question-
Translation- is formation of protein based on the information present in the mRNA.
mRNA ----->> Protein
mRNA after the transcription moves out of the nucleus and enter the cytoplasm and act as template for protein synthesis. Enzyme aminoacyl tRNA synthetase has two binding sites. one recognizes methionine amino acid and binds with the ATP molecule and activate the amino acid called charged tRNA ans released from the aminoacyl tRNA synthetase enzyme and initiate the translation process.
Initiation- Small subunit of ribosome binds with the mRNA which contains codon and recognizes initiation codon AUG. at this point the tRNA that posses the anticodon UAC pairs with the AUG codon of mRNA after that large subunit of ribosomes combined with the small subunit of ribosomes. the large subunit have E site called exit site, P site or peptidyl site and A site or acceptor site and form the initiation complex.
Elongation- during elongation another molecule of tRNA carrying amino acid fits in the A site of large subunit and peptide bond formation takes place between methionine and second amino acid at P site. after that the met tRNA become deaceylated and shift to E site and dissociates from E site. same time the ribosome unit moves one codon in right direction and at the same time another tRNA containing the amino acid comes at A site and peptide bond formation takes place and chain formation takes place at P site.
Termination- Occur when either release factor bind with the A site of termination codon or stop codon such as UGA, UAA, UAG is observed. after that the chain is released from the P site of ribosomes then tRNA, ribosomes large and small subunit also dissociates.
so based on the question -
mRNA reading frame are translated in the 5′→3′ direction into amino acids to form a polypeptide chain.
lets suppose the mRNA have sequence such as
3' AUGACUUUGAAUCGCACGCUAUAA 5'
Amino acid chain will be as Met- Thr- Thr- Asn-Arg-Thr- Leu
1st Amino acid | 2nd amino acid | 3rd Amino acid | 4th Amino acid |
Met | Thr | Thr | Asn |
(A). Find the electrical potential
V(outside) - V(inside) if R(K) = 1 ohms and R(Na) = 10 ohms
(B). Find the electrical potential V(outside) -
V(inside) if R(K) = 10 ohms and R(Na) = 1 ohms
Note: If possible, an explanation would be greatly
appreciated
OUTSIDE Ek 1/10 v ENa- 1/20 v Na cell membrane INSIDE
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