Question

SSE A woman has type B bloodand a man beste blood besides, he is suf fering from hypophosphatenticrickets the one is located in the X chromosome healthy son has the blood termine the probability of a birth: a) a sickson with type A blood b) a health her with type A blood, c) sick daughters with type AB blood. 2. What are the children of a tall woman and man with middle stature if his mother was very tall? What is their relationship 3. Acatalasia is an autosomal recessive trait: the penetrance of the gene that caus- es it is equal 50%. What is the probability of having a sick daughter in healthy heterozygous parents? 4. Fill in the table by using the genetic code: Double-stranded DNA mRNA Amino acids in a protein 5. Analyse the pedigree. Determine mode of inheritance and genotypes of per- eons II. II. III. III. IV, and IV;. What is the probability that the child of a pro- and will have a trait? T 0129991 100 000 v 2. uring 6 years 3 thousand children were born in a city, and 30 of them had Witary recessive disease. What part of the population is a heterozygous carrier harmful gene? Answer by percentage.

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Answer 1

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0 31 de Juni koed group pendizes posible ha Aslase phenotypes & Cox pronetype : xx xx fuite daughters Ex 1 Healthy J. Buckily sick www.wind A Help N.NL L awl who patay . As Vy 1 bod . OM piele w hoo.cl Publility Luttig daug daw n. - Table gol034 1 a Prusenbility of the sick daughters > Thorbertility Of Ars cleart gap - Vy Totul paludt; = 1

dus Acabalasia gene Penetrance of son & Ani Healthy heterogenous paunts Aa x Aa AA Au Au ana u Probability of having a sick progeny = a daughter Penetrance = 1/2 Total probability - 1/4 X 1/2 x 1/2

dung 4 Sequence of ds DNA : ACT TGA GGA CAA TTT CCT GTT A A A rence of mRNA : ACU GGU CAA UUU Amino acid in protin : Glutamine Threonine Cilycine agais (The) (crey) (Coln) Shenylalanine (F)

ans 2) THis is because of coming together of two alleles accounting for tall trait, from both the parents.(Law of independent assortmant)