In Drosophila , the genes sr and e are linked. Recombination frequency = distance between the genes = 8 %
The genotype of heterozygous female fly is : sr e+ / sr e+.
It will produce four type of gametes : sr+ e+, sr e, sr e+, sr e+. The heterozygous genotype of female is possible due to the crossing over event between homozygous parents (sr+ e+ / sr+ e+) and ( sr e / sr e).
Thus the gametes sr+ e+ and sr e of the heterozygous fly represent the parental types and the gametes sr e+ and sr+ e represent the recombinant types.
The proportion of her containing the sr e alleles = (100 - 8)/2 = 46 %
The proportion of her containing the sr+ e+ alleles = (100-8)/2 = 46 %
The proportion of her containing the sr e+ alleles = 8/2 = 4 %
The proportion of her containing the sr+ e alleles = 8/2 = 4 %
In Drosophila, the genes sr (stripe thorax) and e(ebony body) are located 8 CM apart on...
In Drosophila, the genes sr (stripe thorax) and e ebony body) are located 8 CM apart on chromosome 3. The wild type alleles, sr+ and e+, are dominant over the mutant alleles. Consider a female fly that is heterozygous at both loci with the phase: sre+ / sr+ e The proportion (%) of her gametes containing sr e alleles is expected to be The proportion (%) of her gametes containing sr+ e+ alleles is expected to be The proportion (%)...
can you please help me with number 4? An example of linked genes in Drosophila The genes for wing shape and body color are linked (they are on the same chromosome) Drosophila and linked genes In the example shown left, wild type alleles are dominant and are given an upper case symbol of the mutant phenotype (Cu or Eb). This notation used for Drosophila departs from the convention of using the dominant gene to provide the symbol. This is necessary...
In Drosophila (fruit flies) the genes how, dumpy and ebony are located on chromosome 3. LOF = loss of function. Flies homozygous for a LOF mutation (no gene product made) in ebony have dark black bodies. Flies homozygous for a LOF mutation (no gene product made) in dumpyhave truncated (short) wings. Flies homozygous for a partial LOF mutation (some gene product made but significantly less than normal) in how have wings that will not fold down (held out wings; that's...
37) The genes for mahogany eyes and ebony body are chromosome III in Drosophila. Assume that a mahogany-eyed female was mated to an ebony-bodied male and that the resulting F1 phenotypically wild-type females were mated to mahogany, ebony males. Of 1000 offspring, 325 were mahogany, 375 were ebony, 125 were wild type, and 125 were both mahogany and ebony. What is the distance between the mahogany and ebony genes? A) 50 CM B) 15 CM C) 25 CM D) 75...
Question 5 In Drosophila, ebony body (e) and rough eyes (r) are encoded by linked autosomal recessive genes on the third chromosome and are completely linked at O map units apart. A homozygous ebony female was crossed to a homozygous rough male. The F1 were all wild ty The F1 females were crossed to ebony, rough males. Give the phenotypes and their proportions in the F2. ebony, rough 20%, wildtype 20%, ebony 30%, rough 30% ebony, rough 30%, wildtype 30%,...
43. Genes a and b are X-linked and are located 7 mu apart on the X chromosome of Drosophila. A female of genotype a+ b/a b+ is mated with a wild-type (a+b+/Y). a. What is the probability that one of her sons will be either a+b+ or a b+ in phenotype? b. What is the probability that one of her daughters will be a+b+ in phenotype? 44. Three recessive autosomal mutations in Drosophila: a versus wild-type A. b versus B,...
In Drosophila (fruit flies) the genes how, dumpy and ebony are located on chromosome 3. LOF = loss of function. Flies homozygous for a LOF mutation (no gene product made) in ebony have dark black bodies. Flies homozygous for a LOF mutation (no gene product made) in dumpy have truncated (short) wings. Flies homozygous for a partial LOF mutation (some gene product made but significantly less than normal) in how have wings that will not fold down (held out wings;...
Genetic Linkage The six genes listed below are all located on Chromosome 2 of Drosophila melanogaster. Your goal is to construct a genetic map of Chromosome 2. That is, determine the order of these genes along chromosome 2 and the map distance in centimorgans between each gene. To complete this task, you will be given the results of a variety of two-point test crosses involving these genes. For each test cross you may assume that the female is heterozygous and...
The genes for sepia eye color, short bristles, and dark body coloration are on the same chromosome of Drosophila melanogaster. Each gene has two alleles: wild type, which is dominant, or mutant, which is recessive. se+ is dominant and causes red eyes; se is recessive and causes sepia eyes sb+ is dominant and causes long bristles; sb is recessive and causes short bristles b+ is dominant and causes gray body coloration; b is recessive and causes dark...
Assortment of genes on same chromosome In the fruit fly Drosophila, there is a dominant gene for normal wings and its recessive allele for vestigial wings. At another gene locus. there is a dominant gene for red eyes and its recessive allele for purple eyes. A female that was heterozygous at both gene loci was mated with a male that is homozygous for both recessive alleles. Knowing this, complete the sentences with the correct terms. 94% crossing over independent assortment...