Question

12. From the Lineweaver-Burk graph given: a. What are the Km and Vmax for the uninhibited case? b. What type of inhibition is occurring? c. Shown on the page after the Lineweaver-Burk plot are semi-qualitative sketches for three V vs. (S) plots. Which one of these most likely corresponds to this particular experiment (A,B or C)? Scani explain th Cant catimer

Answer 1

a. The intersection of both lines is -1/Km. According to the graph, -1/Km for the uninhibited case = -20 L/uM. So, Km = 0.05 L/uM; Again, the intersection of the lines with the y-axis is the 1/Vmax of the equation. So 1/Vmax for the uninhibited case is= 6 min/uM, so Vmax = 0.166 min/uM

Again Vmax can be calculated from the formula, slope = Km/Vmax

b. This is an example of non-competitive inhibition.

c. The B graph has the most similarity with the non competitive inhibition graph of the experiment conducted.