Question

Consider a series RC circuit as in the figure below for which R = 2.40 MΩ, C = 6.80 μF, and = 32.0 V.

The circuit is a rectangular loop. The bottom side of the loop has a battery labeled emf ℰ, oriented with the positive terminal to the right of the negative terminal. The right side has a resistor R. The top side contains an open switch S. The left side has a capacitor C.

(a) Find the time constant of the circuit.
s

(b) Find the maximum charge on the capacitor after the switch is thrown closed.
μC

(c) Find the current in the resistor 10.0 s after the switch is closed.
μA

Answer 1

solution Given. Resistance R=2.40 MR = 2:4x10or capacitance c= 8. & MF = 6.8x 10 of Ene E = 32 V It is RC transient circut where charge gets deposited accumulated on the capacitor according to q = 20 (1- ē EIRC) - (1) Where to=cę (a) Time constant =RC capacitance Z = 2-4x 106 x 6-8x156 = 16.325 (6) Maximum charge q=ce = 6.88106 x 32 Cobtained after a long time of switching [q=247.6 MCL (c) on differentiating equation (1) we get Variation of current in the circent. Iz da = & etike

Hence . cussent at t= to see I (t= 10) = 32, ē 2-4x10G I = 13.33x106 & 0.3125 I = 13-33x10 6 x 0.7316 = 9.75 8106 A I = 9.75 A