Solution is given below:
Solution: 13. Given Blue eyes (B) Strong jaw (s) / dominant diniples (1) J Parts ... brown eyes (b) 7 weak jaw (3) Recessive ne dimples (d) _ I traits. T Type parentallinen 40 SCO- (single cross over) Parental I child's phenotype frequency I genotype blue eyes, weak jau, dinebles y 4o BPD brown eyes, strong jang | 255 / 6SD 1 dimples as I brown, strong, no cembley brown, weak, bsd dimples blue eyes, strong, dimples 85) 34 SCO-I SCO- (Double (yessover) 1. BSd SCO-T 270 Bod blue, strong, - no dimples blue, weak, no L no dimples brow, weak, no no ciuples Parental Inod 5 bod l Dco. Parcuts ajo pa A Gametes :- Bb So Dd x Bb Sa Dd yes & strong jaw, dimples) - BSD Blue, strong, Dimples d - Bsd - Blue strong, dimples BT - BoD - Blue weak, dimples Bsd Blue weak, no draples - bSD Brown strong, dimples - bsd Brouon strong, no diuples b&D - Brown Weat, druples bad Brown, weak, no dimples - 64 Whook method) A DAGADA bl. 2 bodo
A) Phase of alleles of son + B6 Ss Dd hong, Dimples) eyes B) for calculating gene iculating gene order and genetic distance! Gemitic distance = Reconebinahon frequency blow Huese goues g befineen agenes kecombination frequency 3C0 blw a genes + DCO 100 IX 100 bl๖ ๕344 Total progeny. So X100 gew 300-T + DCO 700 201 + 193+15 999 999 genetic distance blive S&B (jaw and eye genes) - 400 y 100 - 40.0TIM = 494 = frequency = 0.40 DCO 0 genetic distance Y100 40.34 +1+5 999 8 0. 999 SCO -I 999 - blue BAD. X100 a frequency = 0.08 Parental ? etto 360 Ő B Gene order = [5, 6, D.
Coefficient of Luterferance = '- coefficient of coincidence- (0) given. Number of observed Dco dea served (coincidence Coeff.) Number of expected Deo No. of expected DCO = Expected Dco frequency x Total no. of progeny Expected Dco frequency = 'frequency of SCO-5 x Frequency of SCO-IL = 0.40 X0.08 -0.32 i No. of expected Dco = 0.32 x 999 ACES - = 0.1875 32 Hence, E -1 0 .1875 ( coeff. cf Interference) = 10.8125] Ans