i - According to the Lineweaver-Burk equation
Comparing this equation with Y=aX + c
where a is the slope and c is the intercept
so V max = 1/intercept
For Uninhibited State.
y = 1.1437x + 0.013
1/Vmax = 0.013
Vmax = 1/0.013= 76.9 umol/min
Km/Vmax is equal to slope
Km/76.9 = 1.1437
Km = 76*1.1437
= 87.97 umolL-1
For inhibited state
y = 5.4546x + 0.0133
1/Vmax = 0.0133
Vmax = 1/0.0133= 75.6 umol/min
Km/Vmax is equal to slope
Km/75.6 = 5.4546
Km = 75.6 * 5.4546
= 334.93 umolL-1
ii - Type of inhibition is competitive as Vmax is almost same but Km is increased.
iii- Kmapp = Km (1 + [I]/Ki)
Kmapp = 334.93 umolL-1
Km = 87.97 umolL-1
I = 10 umolL-1
334.93 = 87.97 (1+ 10/Ki)
334/87.97 = (Ki +10)/Ki
3.8 = (Ki +10)/Ki
3.8Ki = 10+Ki
10 = 3.8Ki -Ki
10 = 2.8Ki
Ki = 10/2.8 =
Ki = 3.571 umolL-1
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7) The activity of L-aspartate 4-carboxylase can be assayed by following the evolution of CO2 from...
The activity of L-aspartate 4-carboxylase can be assayed by following the evolution of CO2 from L-aspartate: L-aspartate à L-alanine + CO2 . The following results were obtained without an inhibitor and with an inhibitor: Initial velocity (μmol CO2 min-1 ) Concentration of L-aspartate No Inhibitor With Inhibitor (μmol L-1 ) 25 17.0 ---- 33.3 21.3 5.7 50 27.8 8.1 100 41.7 14.7 200 52.6 25.0 i) Calculate the Km and Vmax of the reaction; ii) What type of inhibition is...