Question

The genes for fin length and color are so far apart on the same chromosome that an excess of recombinant progeny was observed. Question 4 16.5 pts In the goldfish, the allele for dark color (C) is dominant to that for albino (c) and the allele for long fins (L) is dominant to the allele for short fins (1). A dark, long-finned goldfish is crossed to an albino, short-finned goldfish and the following phenotypes are observed in the progeny: Phenotype Number Dark, short fins 420 432 Albino, long fins 72 Dark, long fins Albino, short fins 76 Total = 1000 What is the map distance between the gene for fish color and the gene for fish fin length? 14.8% 8.52% 148% 85.296

Answer 1

Solution for the given problem is attached hereby.

Solution 4: albino Dark coloured long-finned Dark coloured sodinned X x - short finned goldfish Progeny : Number 420 7 0 Jo 432 Phenotype Dark, short fins 7 Parental types Albino, long fins Dark, long fins 72 7 Recombinant ones Albeno, short firs Total Map distance blow the gene for fish colour and gene for fin length = Recombination frequency blue the 76 1000 towo - Number of recombinants x 100 Total number of phenotypes - 148 x 100 = /14.814". Aus 1000