0%
The mother is heterozygous for the syndrome, hence let us assume her genotype to be XX, while the man is normal, hence his genotype will be XY. Their children will have following genotypes:
Gametes | X | X |
---|---|---|
X | XX = normal daughter | XX = carrier daughter, phenotypically normal |
Y | XY = normal son | XY = affected son |
Hence, there is a 0% probability of the yet to be born female baby to be afflicted with the disease.
Lesch-Nyhan syndrome is inherited through an X-linked recessive allele. Afflicted children can be identified by self-mutilation...
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