Question

24. It was recently (when some of you were high school freshman :-) discovered that it is possible to obtain information on fetal genotype based on the low number of fetal cells circulating in a pregnant woman's bloodstream. Assume that 1% of all cells in a pregnant woman's bloodstream are from the fetus. You performed high-throughput sequencing of Jane Doe's blood, and for the beta globin gene obtained the following results: 5'-ACTCCTGAGGAGAAG-3' 5'-ACTCCTGTGGAGAAG-3' (wild type allele) (Hbbs allele) 9,950 reads 50 reads What is the most likely conclusion from this experiment? a. Jane Doe is heterozygous for the sickle cell anemia allele b. The fetus is homozygous for the sickle cell anemia allele c. The fetus is heterozygous for the sickle cell anemia allele d. A mosquito carrying Plasmodium falciparum must have bitten Jane before the blood test e. a and b are true
pplease explain

Answer 1

Answer 24:) Option c

Percentage of HbS alleles in total reads = 50/10000 x 100

Percentage of HbS alleles in total reads = 0.0005 x 100

Percentage of HbS alleles in total reads = 0.05%

The percentage is below 1% of fetal cells, which constitutes that this analysis is belonged to fetal blood. This genotype represents the heterozygous genotype.

Answer 16:) Option d

The option d is not correct. Because mutant ade1 can grow on SAICAIR supplement. Other options are correct.

Answer 17:) Option c

The size of gene digestion by Sau3AI = 4

Possible number of variations in 4 bp sequence = nn

Here n is the number of bp.

Possible number of variations in 4 bp sequence = 44

Possible number of variations in 4 bp sequence = 256

Therefore, option c is the correct answer.

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