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In this set of questions, you will need to be able to apply inheritance patterns of two different characters/genes. One gene is inherited in a sex-linked pattern, while the other gene is inherited through an autosomal gene. (Answer choices include 0, 0.25, 0.5, 0.75, and 1.)In this set of questions, you will need to be able to apply inheritance patterns of two different characters/genes. One gene

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From the family history we obtain the genotype of the couples

1) The probability that the daughter with normal color vision and widow's peak who is heterozygous for both gene is 1(100%). Because there is only one daughter with widow's peak and normal vision in F1.

2)The probability that any son the couple has with colorblindness and straight hairline will be 0.5(50%).Because the couple has two sons.Out of these two sons one has colorblindness and straight hairline.

3)The probability that any daughter the couple has with colorblindness and widow's peak will be zero.Because the couple will produce two daughters.Out of these two daughters none of them have colorblindness with widow's peak.

4)The prbability that the couple has a child which must be a son with widow's peak will be 0.25(25%).Because they will produce 4 offspring.Out of these offspring only one child who is a male with widow's peak.

I am providing the cross here

Father Aa X Y and mother aaxcxc Ay widows peak ay straight hairline x as colour blind XC - Normal vision cross between Aaxy

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