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Answer 1

Answer #1

Answer:- equation and calculationto find $\bigtriang$ $\bigtriangleup$ G is as follow:-

AG = AGO+ RTing = 7.53 + 0.008314 x298 x-1.69897 = 7.53 - 4.2093 = 3.32 kj/mol

where G0 is free energy 7.53 kj/mol

R is ideal gas constant =0.008314 kj/mol-k

T is absolute temperature 298k

ln Q is natural logarithm of reaction quotient = ln (0.00200/ 0.100)m =ln(0.02)m = -1.69897m

Answer 2

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