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2. (10pts) In an area on the East coast of Africa with minimal medical facilities the fitness of HbA/HbA = 0.3, of HbA / Hbs

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a. In case of this,the frequency of the alleles has to find out using the before selection criteria. Therefore the frequency of the allele A will be equal to2*.71+0.22/3 = 0.546

Frequency of allele S =(0.14+0.22)/3 = 0.12

b. Considering the situation of the after selection the condition will be

Frequency of allele A = 2*0.3+1.0/3=0.6+1.0/3 = 0.533

Frequency of allele S = 2*0.2+1.0/3= 0.4+1/3 = 0.466

C. The frequency criteria after the selection will be similar to the condition which has been mentioned in the answer b for the next generation and the frequency ratio will match accordingly.

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