Question

distribution with mean 70 and standard deviation 3. Specimens are acceptable for machining only if their hardness is greater than 65. What percentage of speci mens will be acceptable? 17. If the mean value of the weight of a particular brand of dog food is 20.6 lb and the standard deviation is 1.3, as- sume a normal distribution and calculate the amount of product produced that falls below the lower specifica- tion value of 19.7 lb 18. For the CD data frop centafthe CD ine what per- nd below the s o tion of a machin runoff pieces mpled, ation of 19. 90 per pulation car seats to iner mecha- 5 and a stan- t confidence n mean
Please solve for 17 and show all work.

Answer 1

In the question, X bar =20.6

Standard deviation =1.3

Xi=19.7

Z value = (Xi –X bar)/standard deviation

Z value = (19.7-20.6)/1.3

Z value =-0.69

For a z value of -0.69, the Left Tail Area is 0.245097 with the probability of 24.51%.

.

Thus the quantity of product produced which lies below the lower specification limit as given as 19.7 lbs is 24.51%

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