Solve the system by the substitution method
{y=-4× +1
{3x-4y=15
Solve the systems of equations by substitution #11 2x-y-2 3x+4y-6 Solve each system by elimination or by any convenient method #13 a) 3x+4y-1 2x-3y-12 b) -4x+3y--!5 3x-2y-4
Solve the following system by the substitution method. Check
the solution.
Solve the following system by the substitution method. Check the solution. 3x + 4y = 33 X = y +4 Select the correct choice below and, if necessary, fill in the answer box to complete your choice O A. The system has a single solution. The solution set is { } (Simplify your answer. Type an ordered pair.) O B. There are infinitely many solutions. The solution set is...
Solve the system of linear equations using the elimination method x 4y z 18 3x y 4z 9 x 4y 4z 15 - + The unique solution to the system is (Type an exact answer in simplified form.)
Solve the system of equations using matrices. Use the Gaussian elimination method with back-substitution 3x + 3y + 6z = 12 3x + 2y + 2z = 7 2x + 4y + 192 = 11 The solution set is {000) (Simplify your answers.) ha ancier hovee
of equation Solve the system 3x + 4y = -14 5x+7 y = -25
Solve the following system of equations. 2x+4y = 8 3x + 4y = 16 x = 0 Olo X y = -1
Solve the system of equations using matrices. Use the Gaussian elimination method with back-substitution. x+4y=0 x+5y+z=1 2x-y-z=31 The solution set is (___, ____ ,____)
Use the Gauss-Jordan method to solve the following system of equations. 3x + 4y - 2z = 0 5x y + 3z = 1 8x + 3y + z = 1 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution is 000 in the order x, y, z. (Simplify your answers.) B. There is an infinite number of solutions. The solution is (Q10.2), where z is any real number...
(a) 3x-4y 8 Solve for y.
Systems of Equations: 3x + y = 6 2x-2y=4 Substitution: Elimination: Solve 1 equation for 1 variable. Find opposite coefficients for 1 variable. Rearrange. Multiply equation(s) by constant(s). Plug into 2nd equation Add equations together (lose 1 variable). Solve for the other variable. Solve for variable. Then plug answer back into an original equation to solve for the 2nd variable. y = 6 -- 3x solve 1" equation for y 6x +2y = 12 multiply 1" equation by 2 2x...