Question

Label all bonds in CH2Br2.

Label all bonds in SO2.

Label all bonds in NF3.

Label all bonds in BF3.

Answer 1

The molecule is CH2Br Br Br dibromomethane The molecule is a derivative of methane. The central atom carbon is bonded to two hydrogen atoms and two bromine atoms. All the bonds are sigma bonds. Write the electron configuration of the atoms as shown below. C(6): 1s22s22p2 Br(35): [Ar]3d104s24p5

As valency of carbon is 4, it can form maximum four bonds. Each of the hydrogen and bromine atoms can form a single bonds with carbon. In this moecule carbon undergoes sp3 hybridization to form four bonds, bromine uses its single electron that is present in the p-orbital. Hydrogen uses it Is electron to form sigma bond. No pơ bonds are formed in the molecule Label the hybrid orbitals of the molecule as shown below a: C(sp3)-Hs) o: C(sp3)-Br(p) a: C(sp3)-Hs) a: C(sp3)-Bríp)

Answer 2

In СЊ3x molecule, central atom carbon undergoes Sp3 hybridization and forms four sp3 hybridized orbitals. These hybridized orbitals forms a sigma bonds with 1s orbitals of hydrogens and forms a sigma bond with p-orbital of the bromine. ơ: C(sp3 )-H(s) a: C(sp3) H(s) a: C(sp3)-Br(p) a: C(spBr() 2. In SO2 molecule, Sulfur atom undergoes sp2 hybridization and forms three sp2 hybridized orbitals. It forms a sigma bond with p-orbital of one oxygen and forms a pi - bond by parallel overlap with another p-orbital of oxygen. It forms sigma bond with oxygen of p-orbital. Sulfur has one lone pair in sp2 hybridized orbital.

r: S(p)-O(p) lone pair in sp2 orbital o: S(sp2)-0(p) ơ : S(sp2)-O(p) 3. Nitrogen undergo sp3 hybridization and forms 4 sp3 hybridized orbital one orbital has one lone pair of electrons other three sp3 hybridized orbitals forms a sigma bond with p- orbital of Florine atoms.

lone pair in sp3 orbital N(sp3)-F(p) 0% N(sp3)-F(p) 4. In BF3 molecule boron undergoes sp2 hybridization and forms three sp2 hybridized orbitals. These three hybridized orbitals form a three sigma bonds with three p-orbitals of Florine atoms. Reaming p- orbital in boron atom is empty. Empty p-orbital B(sp2)-F(p) B(sp2)-F(p) B(sp2)-F(p)