Question

For each of the below codes, determine if the following MATLAB codes produces an error. • If the code does NOT produce an error, predict the output. • If the code DOES produce an error: (1) state what line the FIRST error is found and what the error is ICE08B-1: clear;clc SICE08B-1 A = [1,5,2,9,4,9]; B(1,5) = 0; counter = 1; for i = 1:length(A) B(1) = A(i) * counter; B(1) = B(i)-2; counter = counter + 1; end ICE08B-2: clear;clc SICEO8B-2 A - [1]; B = [3]; C - [5,4,3,2,1,0]; for i - 1:length (C) A(1+1) = B(1) - mod (B(i), 3); B(i+1) = c(i) - A (i+1); end ICE08B-3: clear;clc SICEO8B-3 A = ones (5,5); B = zeros (6,6); for n = 1:5 A(6,n) =2; end C - A+B ICE08B-4: clear;clc SICEO8B-4 A(1) = 3 B(1) = 5 counter = 1 for i = 1:10 A counter+1) = mod (1,A()); counter = counter+1; end counter

Answer 1

1. The first code does not product any error.

OUTPUT:

B=

-1, 8, 4 , 34, 18, 52

octave:2> A= [1,5,2,9,4,9]; octave:3> B(1,5)=0; octave: 4> counter=1; octave:5> for i= 1: length(A) > > B(i)=A(i)*counter; > > B(i)=B (i)-2; > > counter=counter+1; > > end octave: 6> B B = -1 8 4 34 18 52

Explanation:

A= 1, 5, 2 , 9, 4, 9

B= 0, 0, 0, 0, 0

counter=1

for i = 1 to length(A) i.e.,

i = 1 to 6

• i = 1
• B(1) = A(1)*counter =1
• B(1)=1-2= -1
• counter=counter+1 =2

Now i=2

• B(2)= A(2)*counter = 5*2= 10
• B(2)= B(2)-2 =10-2= 8
• Counter=counter+1 =2+1 =3

Hence the loop executes till the value of i is equal to 10 and the value of counter increases by 1 everytime for loop block is executed.

Hence counter=1

2. Code produces error:

The error is : A;

; is undefined symbol.

To output the value of A.. it should be simply written A and not A;

So it does not output anything.

octave:2> A=[1]; octave:3> B=[3]; octave: 4> C=[5,4,3,2,1,0]; octave:5> for i=1:length(C) > > A(i+1)=B(i)-mod(B(i),3); > > B(i+1)=C(i)-A(i+1); > > end octave: 6> A; octave:7> B B = 3 2 4 0 2 1 0

3. The code is not able to add A+B

Because final matrix A has different dimension i.e., size( 6*5)

And Matrix B has different dimension i.e., size(6*6)

Therefore it is not possible to execute:

C=A+B

Final values of A and B

octave:2> A=ones (5,5); octave:3> Brzeros(6,6); octave: 4> for n=1:5 > > A(6,n)=2; > > end octave:5> C=A+B error: operator +: nonconformant arguments (opl is 6x5, op2 is 6x6)

octave:5> А А = 1 1 1 1 1 2 1 1 1 1 1 2 1 1 1 1 1 2 1 1 1 1 1 2 1 1 1 1 1 2 octave: 6> B В = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

A and B cannot be added.

4. The code does not produce any error. It works fine.

The output is:

Counter=11

octave:2 A(1)=3 A = 3 octave: 3> B(1)=5 B = 5 octave: 4> counter=1 counter = 1 octave:5> for i=1:10 > > A(counter+1)=mod(i,A(i)); > > counter=counter+1; > > end octave: 6> counter counter = 11