A box contains about 6.68 x 10^21 hydrogen atoms at room temperature 21 degrees C find...
Homework Answers
Solution :
Given :
N = 6.68 x 1021
T = 21oC = 294.15 K
Since thermal energy is given by : E = (3/2) N kB T
Where, kB = 1.3807 x 10-23 J/K.
Thus : E = (3/2)(6.68 x 1021)(1.3807 x 10-23 J/K)(294.15 K) = 40.69 J
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