Question

The electric field 54.0 cm from a very long uniform line of charge is 678 N/C. How much charge is contained in a 1.00 cm section of the line? Please give your answer in units of pC.

Answer 1

We know that,

Linear charge density = Q / L,

where the Q represents the quantity of charge and L the total length.

we have the total length as 0.54m and the linear density as 678N/C.
So,

678 = Q/0.54

Q = 678 × 0.54 =366.12C

This charge is contained in 0.54m which is equivalent to 54cm.

Here we have to find how much charge is contained in 1cm.

So the total number of pieces in 54cm of 1cm each, are 54 pieces

Charge in one 1cm piece = (total charge in 54cm)/ (total number of pieces).

366.12/54

== 6.78C