Calculate the current through the series RLC network at the resonance frequency. Vs = 10<0°, R1...

Question

Question

Answer 1

Answer #1

Solution:-

Above RLC Circuit is at resonance, in the normal situation total impedance will be:

Z= R + jwL- wc

but at resonance :

jwL = jwC

so, Z = R

now current will be:

$I =\frac{V}{Z}$

10 I= ---Ampere .

1 = 0.02188 Ampere

I = 21.88 mA

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Answer 2

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