Question

Please dont copy paste from other user Question. Need to learn step by step solution. Better Shows some graph for this question. Q1- A single-phase half-bridge inverter is used to power a purely inductive load of 100mH. The inverter is supplied from a de source of 300V, and is operated at a frequency of 50Hz using square-wave modulation. a) Determine the values of the fundamental, 3rd, 5th and 7th harmonic load current components. b) Determine the load current THD value.

Answer 1

(a) Fundamental, 3rd, 5th and 7th Fourier series of output voltage V_on = 4 times V_s/2/nPi sin (nwt) current I_on = 2V_s/wLn Pi sin (nwt - Pi/2) fundamental n = 1 I_01 = 2 times 300/2Pi times 50 times 100 times 10^-3 sin (wt - Pi/2) I_01 = 19.098 sin (wt - Pi/2) I_orms = 19.098 = 13.5047 Amp [I_orms = 13.5047 A] fundamental 3rd harmonic I_03 = 2 times 300/2Pi times 50 times 3 times 100 times 10^-3 sin (3wt - 3Pi/2) I_03 = 6.366 sin (3wt - 3Pi/2) [I_03rms = 4.501 Amp] 3rd harmonic \r\n 5th harmonic I_05 = 2 times 300/2Pi times 50 times 5 times 100 times 10^-3 sin (5wt - 5Pi/2) I_05 = 3.8196 sin (5wt - 5Pi/2) (I_05)rms = 3.8196/squareroot 2 = 2.70 Amp [(I_05_rms = 2.70 Amp] fifth harmonic 7th harmonic I_07 = 2 times 300/2Pi times 50 times 7 times 100 times 10^-3 sin (7wt - 7Pi/2) [(I_07)rms = 1.929 Amp] 7th harmonic current (b) THD value I_rms = squareroot (I_01)^2 + (I_03)^2 + (I_05)^2 + I_07)^2...