Question

Please help!!

Ouesion 1 Not yet answered Points out of 2.00 P Flag auestion In engineering and product design, it is important to consider the weights of people so that airplanes or elevators aren't overlooded. Based on data from the National Health Survey, we can assume the weight of adult males in the US has a mean weight of 197 pounds and standard deviation of 32 pounds. We randomly select 50 adult males. What is the probability that the average weight of these 50 adult males is over 200 pounds? Give your answer to 4 decimal places. For heip on how to inout a numeric answer, please see 'Instructions for ingutting a numeric response Answer

Answer 1

Solution:

We are given that: Weight of adult makes in the US has a mean weight of 197 pounds and standard deviation of 32 pounds.

That is: Mean = and Standard Deviation =

n = sample size = 50

We have to find the probability that: the average weight of these 50 adult males is over 200 pounds.

That is we have to find:

$z=0.66$

Thus we get:

To get P( Z < 0.66) , look in z table for z = 0.6 and 0.06 and find area.

01 02 03 .04 05 06 07 08 0.0 5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.1 .5398 5438 .5478 5517 .5557 .5 0.2 5793 .5832 .5871 .5910 .5948 5987 .026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 406 6443 .6480 6517 0.4 6554 .6591 .6628 .6664 .6700 .6736 772 .6808 .6844 .6879 0.5 .6915 .6950 .6985 .7019 .7054 .7088 23 .7157 .7190 .7224 0.6-구25ーー 7294ーー7924 . g64 ーー7380 742 .7454 .7486 .7517 .7549 596 .5636 .5675 .5714 .5753

P( Z < 0.66) = 0.7454

Thus