Question

0 Based on a random sample of 1140 adults, the mean amount of sleep per night is 8.42 hours. Assuming the population standard
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution :

Given that,

Sample size = n = 1140

Z\alpha/2 = 1.96

Margin of error = E = Z\alpha/2* (\sigma /\sqrtn)

= 1.96 * (2.9 / \sqrt 1140)

Margin of error = E = 0.17

At 95% confidence interval estimate of the population mean is,

\bar x - E < \mu < \bar x + E

8.42 - 0.17 < \mu < 8.42 + 0.17

8.25 < \mu < 8.59

A 95% confidence interval is (8.25 , 8.59)

option A. is correct

Add a comment
Know the answer?
Add Answer to:
0 Based on a random sample of 1140 adults, the mean amount of sleep per night...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Based on a random sample of 1180 adults, the mean amount of sleep per night is...

    Based on a random sample of 1180 adults, the mean amount of sleep per night is 7.85 hours. Assuming the population standard deviation for amount of sleep per night is 1.4 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD Round to two decimal places as needed.) Interpret the confidence interval O A. O B. ° C. 0 D. We are 95% confident that the interval actually...

  • Based on a random sample of 1140 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1140 ​adults, the mean amount of sleep per night is 8.56 hours. Assuming the population standard deviation for amount of sleep per night is 1.3 ​hours, construct and interpret a 90​% confidence interval for the mean amount of sleep per night. A 9090​% confidence interval is ​(nothing​,nothing​). ​(Round to two decimal places as​ needed.) Interpret the confidence interval.

  • Based on a random sample of 1040 adults, the mean amount of sleep per night is...

    Based on a random sample of 1040 adults, the mean amount of sleep per night is 8.37 hours. Assuming the population standard deviation for amount of sleep per night is 2.7 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD (Round to two decimal places as needed.)

  • Based on a random sample of 1160 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1160 ​adults, the mean amount of sleep per night is 8.49 hours. Assuming the population standard deviation for amount of sleep per night is 3.6 ​hours, construct and interpret a 95​% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (_____​,_______). ​(Round to two decimal places as​ needed.)

  • Based on a random sample of 1080 ​adults, the mean amount of sleep per night is...

    Based on a random sample of 1080 ​adults, the mean amount of sleep per night is 8.41 hours. Assuming the population standard deviation for amount of sleep per night is 3.8​hours, construct and interpret a 90​% confidence interval for the mean amount of sleep per night. A 90​% confidence interval is ​(nothing​,nothing​). ​(Round to two decimal places as​ needed.)

  • For a hypothesis test of the claim that the mean amount of sleep for adults is...

    For a hypothesis test of the claim that the mean amount of sleep for adults is less than 6 hours, technology output shows that the hypothesis test has power of 0.4943 of supporting the claim that 6 hours of sleep when the actual population mean is 3.5 hours of sleep Interpret this value of the power, then identify the value of and interpret that value Interpret this value of the power O A. The chance of failing to recognize that...

  • A random sample of community college students was asked the number of hours they sleep on...

    A random sample of community college students was asked the number of hours they sleep on a typical week-night during a given academic term. The sample data are as follows: 8 6 4 5 3 7 S 4 3 4 4 5 6 8 7 7 7 3 3 4 What is the 90% confidence interval estimate for the true mean amount of sleep time per night spent by community college students during a academic term? a) The data give...

  • The number of hours adults sleep per night is normally distributed with a mean of 7.3...

    The number of hours adults sleep per night is normally distributed with a mean of 7.3 hours. Aussum that the standard devation is unknown. question: if 70% of adults sleep more than 6.5 hours per night, what is the variance? (remember the label)

  • A random sample of 20 recent weddings in a country yielded a mean wedding cost of...

    A random sample of 20 recent weddings in a country yielded a mean wedding cost of $26,387.22. Assume that recent wedding costs in this country are normally distributed with a standard deviation of $8400. Complete parts (a) through (c) below. a. Determine a 95% confidence interval for the mean cost, u, of all recent weddings in this country. The 95% confidence interval is from $to $ (Round to the nearest cent as needed.) b. Interpret your result in part (a)....

  • The results of a national survey showed that on average, adults sleep 6.7 hours per night....

    The results of a national survey showed that on average, adults sleep 6.7 hours per night. Suppose that the standard deviation is 1.9 hours and that the number of hours of sleep follows a bell-shaped distribution. If needed, round your answers to two decimal digits. (a) Use the empirical rule to calculate the percentage of individuals who sleep between 2.9 and 10.5 hours per day. Enter your answer as a percentage. (b) What is the z-value for an adult who...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT