Based on a random sample of 1160 adults, the mean amount of sleep per night is...
Based on a random sample of 1160 adults, the mean amount of sleep per night is 8.49
hours. Assuming the population standard deviation for amount of sleep per night is 3.6
hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night.
A 95% confidence interval is (_____,_______).
(Round to two decimal places as needed.)
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Based on a random sample of 1160 adults, the mean amount of
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Based on a random sample of 1040 adults, the mean amount of sleep per night is...
Based on a random sample of 1040 adults, the mean amount of sleep per night is 8.37 hours. Assuming the population standard deviation for amount of sleep per night is 2.7 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD (Round to two decimal places as needed.)
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Based on a random sample of 1180 adults, the mean amount of sleep per night is...
Based on a random sample of 1180 adults, the mean amount of sleep per night is 7.85 hours. Assuming the population standard deviation for amount of sleep per night is 1.4 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD Round to two decimal places as needed.) Interpret the confidence interval O A. O B. ° C. 0 D. We are 95% confident that the interval actually...
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0 Based on a random sample of 1140 adults, the mean amount of sleep per night is 8.42 hours. Assuming the population standard deviation for amount of sleep per night is 2.9 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (2.) (Round to two decimal places as needed.) Interpret the confidence interval. O A. We are 95% confident that the interval actually does contain the true value...
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1.3.21 Question Help A random sample of 40 adults with no children under the age of...
1.3.21 Question Help A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.88 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mear da y leisure time o 4.02 hours, with a standard deviation o 1.84 hours. Construct and interpret a 95% oonfidence interval or the mean dif erence lnle sure...
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Question 7 5 pts According to research, the amount of sleep per night for U.S adults follows a normal distribution with a mean p = 7.25 hours and standard deviation o - 1.25 hours. Determine the proportion of people who get between 5.0 and 9.0 hours of sleep per night. Use the provided Standard Normal Table (Z table), and provide the proportion as a decimal rounded to four decimal places.
11.3.21 Question Help * A random sample of 40 adults with no children under the age...
11.3.21 Question Help * A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.03 hours, with a standard deviation of 2.42 hours, A random sample of 40 adults with children under the age of 18 results in a mean da y e sure time of 4.14 hours with a standard de ation o 1.86 hours. Construct and interpret a 95% confidence interval or the mean difference...
Based on a random sample of 1040 adults, the mean amount of sleep per night is 8.37 hours. Assuming the population standard deviation for amount of sleep per night is 2.7 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD (Round to two decimal places as needed.)
Based on a random sample of 1180 adults, the mean amount of sleep per night is 7.85 hours. Assuming the population standard deviation for amount of sleep per night is 1.4 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (DD Round to two decimal places as needed.) Interpret the confidence interval O A. O B. ° C. 0 D. We are 95% confident that the interval actually...
0 Based on a random sample of 1140 adults, the mean amount of sleep per night is 8.42 hours. Assuming the population standard deviation for amount of sleep per night is 2.9 hours, construct and interpret a 95% confidence interval for the mean amount of sleep per night. A 95% confidence interval is (2.) (Round to two decimal places as needed.) Interpret the confidence interval. O A. We are 95% confident that the interval actually does contain the true value...
Was the A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.96 hours, with a standard deviation of 226 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4 23 hours, with a standard deviation of 155 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between...
1.3.21 Question Help A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.88 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mear da y leisure time o 4.02 hours, with a standard deviation o 1.84 hours. Construct and interpret a 95% oonfidence interval or the mean dif erence lnle sure...
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