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The weight of boom AB is 750 kg, and the center of gravity is Gı; the weight of cage BCD is 80 kg, and the center of gravity

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B bra biz Ma 8 - - R s. Given that AG,=2m, G, B ² 10m BC=1.5m=QR CD=0.8 MERS m, = 750 kg My = 80 kg Ap ă ñ s. M2 265 kg mis mPorque due to Mzg is Yg = Mgg (As) in clockaise direction As = Aqt QR+RS =(6V3 + 10570-8) :: P = 65x9.8* CV3 +1.5 +0.8) Ir =

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