Question

Question 2 Not yet answered Points out of 1 A student reports the following data for a collision experiment: V1=0.28 V2=0.001 : Vy'=0.09018 V2' =-0.371 where the primes are for the measurements after the collision and the unprimed are before the collision. The mass of the first cart is 1000 grams and the second cart is 500 grams. What is the total momentum before and after the collision from the data? Select one: The momentum before the collision is 0.039 kg m/s and 0.0385 kg m/s after the collision. The momentum before the collision is 0.42 kg m/s and -0.421 kg m/s afterwards. The momentum before the collision is 0.28 kg m/s and the momentum afterwards is 0.276 kg m/s The momentum before the collision is 0.28 kg m/s and the momentum after the collision is -0.095 kg m/s

Answer 1

is Total momentum before collisson p = mavi + m2 V₂ = 180,28 + 0.58 0.001 P = 0.2805 kg mls 6,2 0,28 kgm/s Total momentum after collision P2 = miv,' + m2 V2 = 1x 0109018 - 0.5801371 1 P2 = - 0.09532 kg mla optron here, (d) (Last) momentum is correct not conserved Sweet Selfie