The position of a dragonfly that is flying parallel to the ground is given as a...
The position of a dragonfly that is flying parallel to the ground is given as a function of time by r =[2.90m+(0.0900m/s2)t2]i^− (0.0150m/s3)t3j^.
a) At what value of t does the velocity vector of the insect make an angle of 44.0 ∘ clockwise from the x-axis?
b) At the time calculated in part (a), what is the magnitude of the acceleration vector of the insect?
c) At the time calculated in part (a), what is the direction of the acceleration vector of the insect?
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The position of a dragonfly that is flying parallel to the
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The position of a squirrel running in a park is given by r⃗ =[(0.280m/s)t+(0.0360m/s2)t2]i^+ (0.0190m/s3)t3j^. At 4.75 s , how far is the squirrel from its initial position? At 4.75 s , what is the magnitude of the squirrel's velocity? At 4.75 s , what is the direction (in degrees counterclockwise from +x-axis) of the squirrel's velocity?
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The position of a squirrel running in a park is given by r? =[(0.280m/s)t+(0.0360m/s2)t^2]i+ (0.0190m/s^3)t^3j. 1)...
The position of a squirrel running in a park is given by
r?
=[(0.280m/s)t+(0.0360m/s2)t^2]i+
(0.0190m/s^3)t^3j.
1) At 4.77 s , how far is the squirrel from its initial
position?
2) At 4.77 s , what is the magnitude of the squirrel's
velocity?
3) At 4.77 s , what is the direction (in degrees
counterclockwise from +x-axis) of the squirrel's velocity?
The position of a squirrel running in a park is given by (0.280 m/s)t (0.0360 m/s2)t2]i (0.0190 m/s )t3j
A jet plane is flying at a constant altitude. At time t1=0 it has components of...
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Constants Part A The position of a squirrel running in a park is given by r [(0.280 m/s)t (0.0360 m/s2)t2]i (0.0190 m/s3)t3j Whais (t), the z-component of the velocity of the squirrel, as function of time? O Ux(t) = 0.280 m/s x(t) (0.280 m/s)t (0.0720 m/s2)t2 x(t) (0.0720 m/s2)t O vx(t) 0.280 m/s + (0.0720 m/s*)t Submit Request Answer Part B What is vy(t), the y-component of the velocity of the squirrel, as function of time? uy (t) (0.0570 m/s3)t...
The position of a squirrel running in a park is given by
r?
=[(0.280m/s)t+(0.0360m/s2)t^2]i+
(0.0190m/s^3)t^3j.
1) At 4.77 s , how far is the squirrel from its initial
position?
2) At 4.77 s , what is the magnitude of the squirrel's
velocity?
3) At 4.77 s , what is the direction (in degrees
counterclockwise from +x-axis) of the squirrel's velocity?
The position of a squirrel running in a park is given by (0.280 m/s)t (0.0360 m/s2)t2]i (0.0190 m/s )t3j
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