If n=10, ¯ x x ¯ (x-bar)=49, and s=6, find the margin of error at a 98% confidence level Give your answer to two decimal places.
Solution :
Given that,
Point estimate = sample mean =
= 49
sample standard deviation = s = 6
sample size = n = 10
Degrees of freedom = df = n - 1 = 10 - 1 = 9
At 98% confidence level
= 1 - 98%
=1 - 0.98 =0.02
/2
= 0.01
t/2,df
= t0.01,9 = 2.821
Margin of error = E = t/2,df
* (s /
n)
= 2.821 * (6 /
10)
Margin of error = E = 5.35
If n=10, ¯ x x ¯ (x-bar)=49, and s=6, find the margin of error at a...
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