Question

don't use continuity and break in python 3: (In python3) Exercise # 4: Write a program that prompts for and reads the number ? of spheres to be processed. If ?≤0 your program must display an error message and terminate; otherwise it does the following for ? times: Prompts for and reads the volume of a sphere, it then displays the surface area of the sphere with that volume. Assume that each volume is in cubic centimeters. The program finally displays the average of the surface areas of the ? spheres.

• xercise Write a program that prompts for and reads the number n of spheres to be processed. If n < 0 your program must display an error message and terminate; otherwise it does the following for n times: Prompts for and reads the volume of a sphere, it then displays the surface area of the sphere with that volume. Assume that each volume is in cubic centimeters. • The program finally displays the average of the surface areas of the n spheres. • Please note that = 3.14159. « volume = ſar? • surface area = 4ar? • The following are sample runs of the program. T = Enter number of spheres to be processed: -1 number of spheres must be > 0 Enter number of spheres to be processed: 3 Enter volume of sphere 1: 15 Sphere #1 surface area= 29.41 Enter volume of sphere 2: 27 Sphere #2 surface area= 43.52 Enter volume of sphere 3: 9 Sphere #3 surface area= 20.92 The average surface area = 31.29

Answer 1

Code:

import math

#taking user input
n = int(input('Enter number of spheres to be processed: '))

if(n<=0):
    print('number of spheres must be > 0')
else:
    i = 1
    pi = 3.14159
    sa_sum = 0#sum of all the surface areas
    while(i<=n):
        v = float(input('Enter volume of sphere {}: '.format(i)))
        # calculating the value of r:
        r = math.pow(((3*v)/(4*pi)),1/3)
        #calculating surface area
        sa = 4*pi*r*r
        sa_sum = sa_sum + sa
        #displaying surface area
        print('Sphere #{} surface area= {}'.format(i,round(sa,2)))
        i = i + 1
    
    #calculating average surface area
    avg_sa = sa_sum/n
    print('The average surface area = {}'.format(round(avg_sa,2)))
    

output:

[Pratyushs-MacBook-Pro:python pthapli$ python3 test.py Enter number of spheres to be processed: -1 number of spheres must be > 0 [Pratyushs-MacBook-Pro:python pthapli$ python3 test.py Enter number of spheres to be processed: 3 Enter volume of sphere 1: 15 Sphere #1 surface area= 29.41 Enter volume of sphere 2: 27 Sphere #2 surface area= 43.52 Enter volume of sphere 3: 9 Sphere #3 surface area= 20.92 The average surface area = 31.29 Pratyushs-MacBook-Pro:python pthapli$

Code screenshot:

leggmg ? Py 1 2 import math 3 #taking user input n = int(input('Enter number of spheres to be processed: ')) 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 if(n==0): print('number of spheres must be > 0') else: i = 1 pi = 3.14159 sa_sum = 0#sum of all the surface areas while(i<=n): v = float(input('Enter volume of sphere {}: '.format(i))) # calculating the value of r: r = math.pow(((3*v)/(4*pi)),1/3) #calculating surface area sa = 4*pi*r*r sa_sum = sa_sum + sa #displaying surface area print('Sphere #{} surface area= {}'.format(i, round(sa, 2))) i = i + 1 #calculating average surface area avg_sa = sa_sum/n print('The average surface area = {}', formatai t(round(avg_sa, 2)))