When a gas follows path 123 on the PV diagram in the figure below, 413.0 J...
When a gas follows path 123 on the PV diagram in the
figure below, 413.0 J of heat flows into the system and
171.0 J of work is done by the system.
What is the change in the internal energy of the system?
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How much heat flows into the system if the process follows path 143? The work done by the gas along this path is 58.4 J.
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What net work would be done by the system if the system followed path 12341?
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What net work would be done by the system if the system followed path 14321?
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What is the change in internal energy of the system in the processes described in parts c and d?
Homework Answers
(a) Change in internal energy = heat flow in - work done by the system
U = Q -
W
U = 413 - 171
U = 242 J
(b) Change in internal energy would be same so we can use
U = 242
Q = 242 -
58.4
Q
= 183.6 J
(c) W = 171 - 58.4
W = 112.6 J
(d) This would be -112.6 J
(e) Change in internal energy would be zero
Add Answer to:
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