Question

Question 1a - Increasing Numbers in List - First Occurence(3 points) Write a function numIncreasing1(L) that takes as input a list of numbers and returns a list of the first sequence within that is increasing order, and has a length of at least 2. If no increasing sequential numbers are found, (ie. the input list is in descending order) then naturally a list of just the first value is returned. Increasing sequence means for a number to be valid it has to be greater than the previous. . [5, 2, 1, 3, 4] returns [1, 3, 4], because only the last 3 are in increasing order • [-1, 1, 4, 2, 6) returns [-1, 1, 4] . [5, 1, 8, 9, 10, 100) returns [1, 8, 9, 10, 100] . [4, 1, 2, 3, 4, 2, 4, 6, 8] returns [1, 2, 3, 4] Hint: the break keyword may prove useful to exit a loop def numIncreasing1(L): result = [] for i in range(len(L)): if i == len(L) - 1: result.append(L[i]) else: if L[i] >= L(i + 1]: if result: result.append(L[i]) break else: result.append(L[i]) return result print("Are my sample test cases correct?") print(numIncreasing1([5, 2, 1, 3, 4]) == (1,3,4]) print(numIncreasingl ([2, 1, 4, 5, 6]) == (1,4,5,6]) print(numIncreasingl ([1,2,3,4,4,3,4,5,6,7,7]) == [1,2,3,4]) Are my sample test cases correct? True True True

Answer 1

# do comment if any problem arises

# Code

Q->1b:

def numIncreasing2(s):

    x=[]

    # temporary list

    temp=[s[0]]

    # iterate over s

    for i in range(1,len(s)):

        # check if current order is increasing

        if s[i]>s[i-1]:

            temp.append(s[i])

        else:

            # check for size of temporary list with x

            if len(temp)>len(x):

                # if yes then copy temp to x

                x=temp[:]

            temp=[s[i]]

    # for last element

    if len(temp)>len(x):

        x=temp[:]

    return x

print("Are my sample test cases correct?")

print("#1",numIncreasing2([5,4,3,2,1])==[5])

print("#2",numIncreasing2([1,2,3,4,5])==[1,2,3,4,5])

print("#3",numIncreasing2([1,2,3,4,4,3,4,5,6,7,7])==[3,4,5,6,7])

Screenshot:

5 11 def numIncreasing2 s): x=[] # temporary list temp= [s[@]] # iterate over s for i in range(1, len(s)): # check if current order is increasing if s[i]>s[i-1]: temp.append(s[i]) else: # check for size of temporary list with X if len(temp)>len(x): # if yes then copy temp to X x=temp[:] temp=[s[i]] # for last element if len(temp)>len(x): x=temp[:] return X 17 18 19 25 26 27 | 28 | 29 print("Are my sample test cases correct?") print("#1", numIncreasing2([5,4,3,2,1])=[5]), print("#2", numIncreasing2 ([1,2,3,4,5])=[1,2,3,4,51), print("#3", numIncreasing2([1,2,3,4,4,3,4,5,6,7,7])=[3,4,5,6,7)

Output:

Are my sample test cases correct? #1 True #2 True #3 True

Q->1c:

def numIncreasing(L, longest=False):

    if longest:

        return numIncreasing2(L)

    else:

        return numIncreasing1(L)

Screenshot:

40 42 43 def numIncreasing ( Z, longest=False): if longest: return numIncreasing2(L) else: return numIncreasingi(L) 44 45 46