Question

For the circuit in figure below, the switch has been in position a for a long time. At t=0, it moves to position b. Calculate v(t) for all t>0. 20 ko 20 kΩ a t = 0 1202 + Vo + 20 V 5 F V 40 50 V For v(t) given in the form: v(t)=A+Be-t/c v for t> Enter numerical values (with a negative sign if needed) for the constants A, B and C below: A = B = C=

Answer 1

Solution. at to Switcheet positron e. Copaci yox is fully charged cice . Steadysteriel Now 20kr mm I 2okh Var Vs 1202 I + a tham q you telo) 40 201 sov.G Vi= 200 C from Virtual ground Concept) I= o-V o-vi - y - Va -Po 26 -20=20 - Va ra=thor Na= 4ov so 4+16 10 VLO) = $ 4x Va C applying Voltage divides = 4X yo = lov VO)= lov 464 464

at txo RC Circuit gets isolated from Op-hong- VLO) - Velot ) - lov ® 2okt at ( 40) Circuit 12h va 20K b † 42 velos) sov dov N((o)= 4x50 u+12 opplyingvortege divides 209 16 = 1205 (10)=1205 -the --VEJ = Vot(V10+)-Votre -t/e => 125+ (10-1205) - the VG) = 1205-205. 122 Z= Regol For Req Req 42 sou Short

48 Req= 12x4 1274 16 CIRC - 3*5 =15 (1=5€) Now th 15 v (t) = 1205-205.e A = 1205 B =-205 Ave c=15
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