Using the following regression formula:
Year (X) | Price (Y) | (X-Xm) | Y-Ym | (X-Xm)(Y-Ym) | (X-Xm)^2 | (Y-Ym)^2 |
0 | 0.98 | -5 | -0.475 | 2.375 | 25 | 0.225625 |
2 | 1 | -3 | -0.455 | 1.365 | 9 | 0.207025 |
4 | 1.2 | -1 | -0.255 | 0.255 | 1 | 0.065025 |
6 | 1.55 | 1 | 0.095 | 0.095 | 1 | 0.009025 |
8 | 1.8 | 3 | 0.345 | 1.035 | 9 | 0.119025 |
10 | 2.2 | 5 | 0.745 | 3.725 | 25 | 0.555025 |
Xm = Mean of X = 5 ;
Ym = Mean of Y = 1.455
Using the formula mentioned, we get
To compute the constant term, following formula is used
Thus, we get
Thus, the regression equation is:
To compute the correlation coefficient, following formula is used
We get r = 0.7868 ~ 0.79
The graph of the regression equation is :
This can be seen using the following table, where the value of 't' are put in the regression equation
Year (X) | Price (Y) | Equation |
0 | 0.98 | 0.822 |
2 | 1 | 1.074 |
4 | 1.2 | 1.326 |
6 | 1.55 | 1.578 |
8 | 1.8 | 1.83 |
10 | 2.2 | 2.082 |
To find out the residual, we move a step forward, by subtracting the 'equation' value from the 'Price' value
Year (X) | Price (Y) | Equation | Residual |
0 | 0.98 | 0.822 | 0.158 |
2 | 1 | 1.074 | -0.074 |
4 | 1.2 | 1.326 | -0.126 |
6 | 1.55 | 1.578 | -0.028 |
8 | 1.8 | 1.83 | -0.03 |
10 | 2.2 | 2.082 | 0.118 |
Thus, the answer to last part of the question is option a. The residual is positive at first, then turns negative and finally turns positive at last.
In case of any query, feel free to comment
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