Question

Equilibrium composition (2) K. (3) AG,(T) (9) 15.(T) (10) T JH(T) (11) Conform TC 1H,º (8) AS,O (7)
can someone please explain how this chart works and how to find each value

Answer 1

1. Arrows pointing towards a particular term are inputs required for the calculation of that particular term

2. Arrow pointing away from the term is the output and input for the further calculation of next term.
. It is a Bottom - Up approach. ASI The left tottom is si , it is standard Molar entropy. This ratue is entropy of an element at fired conditions available in standard references for all elements. Referes at standard temp. AS (7): usion = This is entropy change in a reaction { msicproducto) - En sifreactanto) · AS, (T) (10) temperatures not Entropy change at other меча. #tophalo.. AS(T) Asr! + Pver Inputs are = 45, + n AT I Cpi and T are hence required as shown in the flow Chart AS (T) : ast np

Ah Standard enthalpy of formation available in all stand and references H9 (8) Standard enthalpy change for a reaction given by AH = { mAh (products) - Inari (reactant)] AH'IT) (0) AH(1) - AH + All 1H + n(p41. Alt AG (T-Tref) Input on and t are needed as shown in chart. I . 467 (T) (9) With the inputs, AS, (1) , T, AHCT) AG (T) can be calculated using the relation 149. (T) = 44(7) - TAŚCT) AG H- T 45+

ka (3) with the inputs 46 (T) and T AG, (t) = - Rimka where .ka is calculated. E qinlibrium composition (2) From the ka a (A)" LB76 a A+ b B - C + dD equilibrium composition is calculated.