Suppose that an urn contains 10 red balls and 4 white balls. Supposed 3 balls are...

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Answer 1

Answer #1

10 red balls and 4 white balls

P[ Red ball ] = 10/14

P[ White ball ] = 4/14

a) With replacement

P[ 1 red ball and 2 white balls ] = P[ Red ball ]*P[ White ball ]*P[ White ball ]

P[ 1 red ball and 2 white balls ] = (10/14)*(4/14)*(4/14)

P[ 1 red ball and 2 white balls ] = 160/2744

P[ 1 red ball and 2 white balls ] = 0.0583

b) Without replacement

P[ 1 red ball and 2 white balls ] = P[ Red ball ]*P[ White ball | Red ball is drawn ]*P[ White ball | Red and White ball is drawn ]

P[ Red ball ] =10/14

P[ White ball | Red ball is drawn ] = 4/13

P[ White ball | Red and White ball is drawn ] = 3/12

P[ 1 red ball and 2 white balls ] = (10/14)*(4/13)*(3/12)

P[ 1 red ball and 2 white balls ] = 120/2184

P[ 1 red ball and 2 white balls ] = 0.0549

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Answer 2

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