Question

A point charge of 8 μC is located at x = - 2.4 cm, and a second point charge of - 6 C is located at x = 3.1 cm. Where should a third charge of + 6 μC be placed so that the electric field at x = 0 is zero? (Your result must be in cm's. Include 2 digit after the decimal point and maximum of 5% of error is accepted in your answer. )

Answer 1

Koont WTELP Electric Nole o 9 think field ka ris distance suc . - 6 2nd charge will be Joue but since, it is given be I will consider that -2.4cm yks. 1cm for +6MC . -64C suc you I Direction of Ef Direction g Eleclaie I field (EA pl. of charge is edata Let the 3rd s distance a from the origin - buc La Direction of per ac at origan kaxioba so, Efe due Er due to Er due to to auc at origen (2.4x103)2 be at origin K*6). buc at origen Koue (1) (3.1x102721 0819 (xxr82 2 CScanned with CamScanner

о. 5 мга Е. (о о () қ966 (2.4 хуб?) ? " + 6 (3) xia 2 ) 2 ф-- еско" (2 ), 2 4 хуб 2) 2 6 9 х 6xt - О - + - 22. (3,1) 2 (2.4)?- (2.4)2 1) 2 - 1. 58 x) о т 0 - 624 - - 6 0.62 x | o 6x10 c 6xy S6 22 ос - о624 със с. По о. 3. ко 4, 6 і смс кал. - 6 5 Бх | O Якщо по З•1)- 22 (2.4), 6xo 6 (- 39 + о• 6 24 : о" = 2 98 - 1.73 са- CScanned with CamScanner