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15. A circular pipe made of a brittle material has a 100mm inside diameter and a 150mm outside diameter. It is subjected to a
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solutions Given D=150mm d = 200mm T= 70 knm T= 70x100 mm Axial force & P x 103 N. To=250 mpa q=100 mpa Torque causes a shearwith compressive load a normal stress will be P developped. T = Px10² - 5 Cord) T= 0.1018 p upan Normal stress o= 0-10189 upa250+ Co. osoap) – 2x250 x0.osoap = (0.0509 p) + 131-633² IP=1774.96 KN

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