The degeneracy of a system of NA identical molecules A in a three-dimensional box has the form g = V^ (NA) f(EA,NA). If we add NB more molecules of a diferent substance B, keeping the volume constant, what is the new equation for the degeneracy?
if we consider a box i.e. in cubical shape such that a=b=c,energy can be expressed by
E = h2 / 8ma2 ( nx2 + ny2 + nz2 )
for the lowest quantum state ( 111), in which nx ,ny ,nz respectively are equal to unity.it is seen that
E = 3 h2 / 8ma2 there is only set of quantum numbers that gives this energy state& this level is
said to be non degenarate.
if we now consider the second energy state there are three sets (112) (121) (211 ) of the quantum numbers
nx ,ny,nz that will give the same energy level, E = 3h2 /4ma2 such level is said to be degenarate&this
particular level is said to degenarate&in this particular level is called Triply degenerate. which is based on
degeneracy of the energy levels in a three dimensional box.
thank u
The degeneracy of a system of NA identical molecules A in a three-dimensional box has the...
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