For given sample mean value is
Create the following table.
data | data-mean | (data - mean)2 |
7 | -3.8571 | 14.87722041 |
11 | 0.1429 | 0.02042041 |
12 | 1.1429 | 1.30622041 |
6 | -4.8571 | 23.59142041 |
11 | 0.1429 | 0.02042041 |
13 | 2.1429 | 4.59202041 |
16 | 5.1429 | 26.44942041 |
Find the sum of numbers in the last column to get.
So standard deviation is
t value for 99% CI is TINV(0.01,6)=3.707
So Margin of Error is
So CI is
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