Question

You are working in a factory and have been tasked with determining the electrical needs for a new motor that will be installed on an assembly line. The motor has been tested under load conditions and found to have a resistance of 37.0 2 and an inductive reactance of 51.0 12. We can model the motor as a series RL circuit. The motor will have its own dedicated circuit with an rms voltage of 540 V. You need to determine the peak current (in A) drawn by the motor to determine the size of the circuit breaker needed to protect the circuit. O A. 10.6 A O B. 12.1 A O C. 13.8 A O D. 8.92 A

Answer 1

Given motor com be modelled as RL circuit, Resistance R=37.00 Inductive reactance XL = 51.or. Sourve voltage Vems = 5400 Vsonce Vsource = 540 esin/wt) =rmsinwt. where Vman - Vams X2 fe sinussidal Input Sol The circuit can be drawn as mm R=37R XL=slor V source (US) @ =54062 sinut The current throug the RL circuit combe found by Applying kve - Vs & I (et jxc) VS Vs - I - RtjXL magnitude II1 = R2 ++ (2 Manimum current Iml = √2 VORMS ✓ R²+x22 Vm FR2X22 540x52 √372 +512 312.12 A manimum current drawn by the I therefore motor = 1212A 12. IA