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1/2.5 points | Previous Answers My Notes You are planning to take to a trip to Montreal, Canada during the month of April and
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Answer #1

Given,

Mean = E(X) = \mu = 10.1

Standard deviation =SD(X) = 4.3

Variance = Var(X) = 4.3^2 = 18.49

The conversion function of X into Y is,

Y = \frac{9}{5}x+32

Q1 )

E(Y) = E\left ( \frac{9}{5}x+32 \right )

E(Y) =\frac{9}{5}E(x)+32 { since , E(aX + b ) = aE(X) + b }

E(Y)= x 10.1 + 32

E(X) = 50.18

Q2 )

SD(Y) = \sqrt{Var(Y)}

Let's find variance first.

Var(Y) = Var\left ( \frac{9}{5}X+32 \right )

Var(Y) = \left ( \frac{9}{5} \right )^2\times Var(X) { Since , Var( aX + b ) = a2Var(X) }

Var(Y) = \frac{81}{25}\times 18.49

Var(Y) =59.9076

So,

SD(Y) = \sqrt{Var(Y)}

SD(Y) = \sqrt{59.9076 }

SD(Y) = 7.74

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