Question

QUESTION 4 A balloon containing 2.1 moles of Helium takes up 2.3 L. If the balloon is opened and the amount of gas is reduced to 1.4 moles of Helium, what is its new volume (in L)? The temperature and pressure are held constant. A. 3.45 B. 1.5 C.8.0 1.3 QUESTION 5

Answer 1

The solution is given below

Molar mass of Helium = 4g Volume of Helium given = 2.3 L No. of moles of Helium (initial) = 2.1 moles No. of moles Helium (final) = 1.4 moles Temperature and pressure is constant in 1st case Pv = nRT p times 2.3 = 2.1 RT 2.3 P = 2.1 RT (1) In 2nd case Pv = nRT pV = 1.4 RT (2) Substituting the value of P in eq (2) P = 2.1 RT/2.3 {From eq(1)} putting �p� in eq (2) 2.1 RT/2.3 times v = 1.4 RT v = 1.4 times 2.3/2.1 V = 3.22/2.1 V = 1.533